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H5PS5162GFRS6C Datasheet(PDF) 62 Page - Hynix Semiconductor |
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H5PS5162GFRS6C Datasheet(HTML) 62 Page - Hynix Semiconductor |
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62 / 64 page  Rev.1.7 / Feb. 2013 62 H5PS5162GFR series 38 When the device is operated with input clock jitter, this parameter needs to be derated by { - tJIT(duty),max - tERR(6-10per),max } and { - tJIT(duty),min - tERR(6-10per),min } of the actual input clock. (output deratings are rel- ative to the SDRAM input clock.) For example, if the measured jitter into a DDR2-1066 SDRAM has tERR(6-10per),min = - 202 ps, tERR(6-10per),max = + 223 ps, tJIT(duty),min = - 66 ps and tJIT(duty),max = + 74 ps, then tAOF,min(derated) = tAOF,min + { - tJIT(duty),max - tERR(6-10per),max } = - 350 ps + { - 74 ps - 223 ps} = - 647 ps and tAOF,max(derated) = tAOF,max + { - tJIT(duty),min - tERR(6-10per),min } = 950 ps + { 66 ps + 202 ps } = + 1218 ps. (Caution on the min/max usage!) 39. For tAOFD of DDR2-1066, the 1/2 clock of nCK in the 2.5 x nCK assumes a tCH(avg), average input clock HIGH pulse width of 0.5 relative to tCK(avg). tAOF,min and tAOF,max should each be derated by the same amount as the actual amount of tCH(avg) offset present at the DRAM input with respect to 0.5. For example, if an input clock has a worst case tCH(avg) of 0.48, the tAOF,min should be derated by subtracting 0.02 x tCK(avg) from it, whereas if an input clock has a worst case tCH(avg) of 0.52, the tAOF,max should be derated by adding 0.02 x tCK(avg) to it. There- fore, we have; tAOF,min(derated) = tAC,min - [0.5 - Min(0.5, tCH(avg),min)] x tCK(avg) tAOF,max(derated) = tAC,max + 0.6 + [Max(0.5, tCH(avg),max) - 0.5] x tCK(avg) or tAOF,min(derated) = Min(tAC,min, tAC,min - [0.5 - tCH(avg),min] x tCK(avg)) tAOF,max(derated) = 0.6 + Max(tAC,max, tAC,max + [tCH(avg),max - 0.5] x tCK(avg)) where tCH(avg),min and tCH(avg),max are the minimum and maximum of tCH(avg) actually measured at the DRAM input balls. Note that these deratings are in addition to the tAOF derating per input clock jitter, i.e. tJIT(duty) and tERR(6-10per). However tAC values used in the equations shown above are from the timing parameter table and are not derated. Thus the final derated values for tAOF are; tAOF,min(derated_final) = tAOF,min(derated) + { - tJIT(duty),max - tERR(6-10per),max } tAOF,max(derated_final) = tAOF,max(derated) + { - tJIT(duty),min - tERR(6-10per),min } |
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