LM27313, LM27313-Q1

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SNVS487E – DECEMBER 2006 – REVISED JANUARY 2015

Typical Applications (continued)

An inductor should be selected with enough inductance to prevent the switch current from reaching 800 mA in

the 0.524 µs ON time interval (see Figure 17):

Figure 17. Discontinuous Design, 5 V – 12 V Boost

The voltage across the inductor during ON time is 4.8 V. Minimum inductance value is found by:

L = V x (dt/dl)

(16)

L = 4.8 V x (0.524 µs / 0.8 mA) = 3.144 µH

(17)

In this case, a 3.3-µH inductor could be used, assuming it provided at least that much inductance up to the 800-

mA current value. This same analysis can be used to find the minimum inductance for any boost application.

8.2.1.2.13

Inductor Suppliers

Some of the recommended suppliers of inductors for this product include, but are not limited to, Sumida,

Coilcraft, Panasonic, TDK and Murata. When selecting an inductor, make certain that the continuous current

rating is high enough to avoid saturation at peak currents. A suitable core type must be used to minimize core

(switching) losses, and wire power losses must be considered when selecting the current rating.

8.2.1.2.14

Shutdown Pin Operation

The device is turned off by pulling the shutdown pin low. If this function is not going to be used, the pin should be

tied directly to VIN. If the SHDN function will be needed, a pullup resistor must be used to VIN (50 kΩ to 100 kΩ is

recommended), or the pin must be actively driven high and low. The SHDN pin must not be left unterminated.

8.2.1.3 Application Curves

Figure 18. Typical Startup Waveform for Vin = 3.3 V, Vout

Figure 19. Typical Startup Waveform for Vin = 5.0 V, Vout

= 12 V

= 12 V

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