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BA6110FS Datasheet(PDF) 4 Page - Rohm |
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BA6110FS Datasheet(HTML) 4 Page - Rohm |
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4 / 7 page ![]() BA6110FS Standard ICs ! ! ! !Attached components (1) Positive input (Pin 1) This is the differential positive input pin. To minimize the distortion due to the diode bias, an input resistor is connected in series with the signal source. By increasing the input resistance, distortion is minimized. However, the degree of improvement for resistances greater than 10k Ω is about the same. An input resistance of 1k Ω to 20kΩ is recommended. (2) Negative input (Pin 3) This is the differential negative input pin. It is grounded with roughly the same resistance value as that of the positive input pin. The offset adjustment is also connected to this pin. Make sure a sufficiently high resistance is used, so as not to disturb the balance of the input resistance (see Figure 3). (3) Input bias diode (Pin 5) The input bias diode current (ID) is determined by this pin. The IC input impedance when the diode is biased, if the diode bias current is ID, is expressed as follows: Rd = ( Ω) 26 ID (mA) (4) Control (Pin 7) This pin controls the differential current. By changing the current which flows into this pin, the gain of the differential amplifier can be changed. (5) Output (Pin 11) The differential amplifier gain (AV) is determined by the resistor RO connected between the output terminal and the Pin 7 control terminal, as follows: Av = gm · RO = ICONTROL (mA) 52 (mV) × RO Make sure the resistor is selected based on the desired maximum output and gain. (6) Buffer input (Pin 12) The buffer input consists of the PNP and NPN emitter follower. The bias current is normally about 0.8 µA. Consequently, when used within a small region of control current, we recommend using the high input impedance FET buffer. (7) Buffer output resistance (Pin 14) An 11k Ω resistor is connected between VCC and the output within the IC. When adding an external resistance between the GND and the output, make sure the resistor RL = 33k Ω. ! ! ! !Application example (1) Fig.3 shows a voltage-controlled amplifier (AM modulation) as an example of an application of the BA6110FS. By changing the ICONTROL current on Pin 7, the differential gain can be changed. The gain (AV), if the resistance of Pin 11 is RO, is determined by the following equation: Av = gm · RO = ICONTROL (mA) 52 (mV) × RO Good linearity can be achieved when controlling over three decades. By connecting Pin 5 to the VCC by way of a resistor, the input is biased at the diode and distortion is reduced. The gain in this case is given by the diode impedance Rd and the ratio of the input resistance RIN, as shown in the following: Av = gm · RO × Rd Rd × RIN The diode impedance Rd = (26 / ID (mA) ) Ω, so that the Pin 5 bias current ID = (VCC - 1V) / R (Pin 5). The graph in Fig. 6 shows the control current in relation to the open loop gain at the diode bias. In the same way, Fig.7 shows the control current in relation to the THD = 0.5% output at the bias point. Fig. 8 shows a graph of the control current in relation to the open gain with no diode bias. Fig. 9 shows a graph of the control current in relation to the SN ratio. Fig. 10 shows a graph of the diode bias current in relation to the SN ratio. Fig. 11 shows a graph of the power supply voltage characteristics. (2) Fig. 4 shows a low pass filter as an example of an application of the BA6110FS. The cutoff frequency fO can be changed by changing the Pin 7 control current. The cutoff frequency fO is expressed as: fO = RA · gm (R + RA) 2πC This is attenuated by -6dB / OCT. Fig. 12 shows a graph of the ICONTROL in relation to the output characteristics. (3) Fig. 5 shows a voltage-controlled secondary low passfilter as an example of an application of the BA6110FS. The cutoff frequency fO can be changed by changing thePin 7 control current. fO = RA · gm (R + RA) · 2πC This is attenuated by - 12dB / OCT. Fig. 13 shows a graph of the ICONTROL output characteristic. |
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