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MIC9130 Datasheet(PDF) 16 Page - Micrel Semiconductor |
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MIC9130 Datasheet(HTML) 16 Page - Micrel Semiconductor |
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16 / 19 page ![]() MIC9130 Micrel, Inc. M9999-040805 16 April 2005 A 16.2 ohm, 1%, non inductive resistor with at least a 50mW rating should be selected. A good choice would be an 0805 size metal film or a 1/8 watt leaded metal film resistor. A series resistor between the current sense transformer and the Isns input is not necessary unless it is used for low pass filtering. If the current sense transformer were not used, the sense resistor would dissipate 1.7 watts. R V I SENSE SENSE SENSE = = = Ω 0 82 5 0 164 . . P I R W DISS RMS SENSE = × = × = 2 2 3 25 0 164 1 7 . . . Slope Compensation Power supplies using peak current mode control techniques require slope compensation when they are operating in continuous mode and have a duty cycle greater than 50%. Without slope compensation, the duty cycle of the power sup- ply will alternate wide and narrow pulses commonly referred to as subharmonic oscillations. Even though the MIC9130 operates below a 50% duty cycle, slope compensation adds the benefits of improved transient response and greater noise immunity in the current sense loop (especially when the current ramp is shallow). Slope compensation can be implemented by adding an optimum 1/2 of the inductor cur- rent downslope, reflected back to the current sense input. In real world applications, 2/3 of the inductor current downslope is used to allow for component tolerances. Slope compensation at the ISNS input may be implemented by using a resistor and capacitor as shown in Figure 12. The rectangular waveshape of the gate drive output is integrated by the resistor/capacitor filter, which results in a ramp used for the slope compensation signal. When the gate drive and the current signal at the sense resistor goes low, the capaci- tor is discharged to 0V. Gate Drive (pin 16) ISNS (pin 14) MIC9130 R2 R1 C1 RSENSE Figure 12 The procedure outlined below demonstrates how to calculate the component values. Compute the inductor current downslope as seen at the cur- rent sense input. For a flyback, buck or forward mode topology the inductor downslope is equal to: M di dt V V L O D 2 = = + where : VO is the output voltage VD is the forward voltage drop of the rectifier diode L is the inductance of the output inductor (or the secondary winding inductance for the flyback topology) M2 is the inductor current downslope For a boost topology, the inductor downslope is: M di dt V V V L OUT IN D 2 = = − + In a transformer isolated topology, the downslope must be reflected back to the primary by the turns ratio of the trans- former. The reflected downslope is: M M Ns Np REFLECTED 2 2 = × where : Ns/Np is the turns ratio of the secondary winding to the primary winding. M2REFLECTED is the inductor curent downslope reflected to the secondary side of the current sense transformer. The reflected downslope is multiplied by the current sense resistor to obtain the downslope at the current sense input pin (ISNS). I M R SNS SLOPE REFLECTED S _ = × 2 where Rs is the value of the current sense resistor. The required downslope of the compensation ramp at the ISNS input is: M ISNS SLOPE 3 0 67 = × _ . R1 is know if a value for the resistor between the current sense resistor and the Isns pin, has already been selected. If not chose a value of 1k, which will minimize any offset and signal degradation at the ISNS pin. Select a value of C1 to minimize signal degradation from the cutoff frequency of R1/C1. The bandwidth should be at least six times the switching frequency. C f R S 1 1 2 1 = × × × ππ where: fS is the switching frequency of the power supply (not the oscillator frequency) The slope of the generated compensation ramp is: M V R1 R2 R1 1 R2 C1 GATE_DRIVE 3 = × + × × Solving for R2 and assuming R2 is much greater than R1. R V R M C GATE DRIVE 2 1 3 1 = × × _ where: VGATE_DRIVE is the amplitude of the gate drive waveform |
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