80C554 datasheet(15/76 Pages) PHILIPS

15 / 76 page

Philips Semiconductors

Preliminary specification

80C554/83C554/87C554

80C51 8-bit microcontroller – 6 clock operation

16K/512 OTP/ROM/ROMless, 7 channel 10 bit A/D, I2C, PWM,

capture/compare, high I/O, 64L LQFP

2000 Nov 10

SMOD1

SMOD0

POF

WLE

GF1

GF0

IDL

PCON

(87H)

SM0 / FE

SM1

SM2

REN

TB8

RB8

SCON

(98H)

STOP

BIT

DATA BYTE

ONLY IN

MODE 2, 3

START

BIT

SET FE BIT IF STOP BIT IS 0 (FRAMING ERROR)

SM0 TO UART MODE CONTROL

0 : S0CON.7 = SM0

1 : S0CON.7 = FE

SU00982

Figure 9. UART Framing Error Detection

SM0

SM1

SM2

REN

TB8

RB8

SCON

(98H)

COMPARATOR

RECEIVED ADDRESS D0 TO D7

PROGRAMMED ADDRESS

IN UART MODE 2 OR MODE 3 AND SM2 = 1:

INTERRUPT IF REN=1, RB8=1 AND “RECEIVED ADDRESS” = “PROGRAMMED ADDRESS”

– WHEN OWN ADDRESS RECEIVED, CLEAR SM2 TO RECEIVE DATA BYTES

– WHEN ALL DATA BYTES HAVE BEEN RECEIVED: SET SM2 TO WAIT FOR NEXT ADDRESS.

SU00045

Figure 10. UART Multiprocessor Communication, Automatic Address Recognition

Mode 0 is the Shift Register mode and SM2 is ignored.

Using the Automatic Address Recognition feature allows a master to

selectively communicate with one or more slaves by invoking the

Given slave address or addresses. All of the slaves may be

contacted by using the Broadcast address. Two special Function

Registers are used to define the slave’s address, SADDR, and the

address mask, SADEN. SADEN is used to define which bits in the

SADDR are to b used and which bits are “don’t care”. The SADEN

mask can be logically ANDed with the SADDR to create the “Given”

address which the master will use for addressing each of the slaves.

Use of the Given address allows multiple slaves to be recognized

while excluding others. The following examples will help to show the

versatility of this scheme:

Slave 0

SADDR

1100 0000

SADEN

1111 1101

Given

1100 00X0

Slave 1

SADDR

1100 0000

SADEN

1111 1110

Given

1100 000X

In the above example SADDR is the same and the SADEN data is

used to differentiate between the two slaves. Slave 0 requires a 0 in

bit 0 and it ignores bit 1. Slave 1 requires a 0 in bit 1 and bit 0 is

ignored. A unique address for Slave 0 would be 1100 0010 since

slave 1 requires a 0 in bit 1. A unique address for slave 1 would be

1100 0001 since a 1 in bit 0 will exclude slave 0. Both slaves can be

selected at the same time by an address which has bit 0 = 0 (for

slave 0) and bit 1 = 0 (for slave 1). Thus, both could be addressed

with 1100 0000.

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