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SC2446AEVB Datasheet(PDF) 18 Page - Semtech Corporation |
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SC2446AEVB Datasheet(HTML) 18 Page - Semtech Corporation |
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18 / 27 page ![]() 18 2005 Semtech Corp. www.semtech.com POWER MANAGEMENT SC2446A R o2 and the current sensing gain, such that the converter output voltage is regulated with satisfactory dynamic performance. With the output voltage V o known, the feedback gain h and the feedback resistor values are determined using the equations given in the “Output Voltage Setting” section with . V 5 . 0 h o = For the rated output current I o, the current sensing gain k is first estimated as . 1 . 2 I k o = From the transfer function from the voltage error amplifier output v c to the converter output vo is . s s 1 s s 1 kR ) s ( G : ) s ( V ) s ( V 1 p 1 z o vc c o + + = = where, the single dominant pole is , C ) R R ( 1 s o oesr o 1 p + = and the zero due to the output capacitor ESR is . C R 1 s o oesr 1 z = The dominant pole moves as output load varies. The controller transfer function (from the converter output v o to the voltage error amplifier output vc) is , s s 1 s s 1 ) C C ( s h g ) s ( C 2 p 2 z 3 2 m + + + = where , C R 1 s 2 2 2 z = and . C C C C R 1 s 3 2 3 2 2 2 p + = The loop transfer function is then T(s)=G vc(s)C(s). To simplify design, we assume that C 3<<C2, Roesr<<Ro, selects S p1=S z2 and specifies the loop crossover frequency f c. It is noted that the crossover frequency determines the converter dynamic bandwidth. With these assumptions, the controller parameters are determined as following. , f 2 hkR g C c o m 2 π = , C C R R 2 o o 2 = and , K R C R C 2 o oesr 3 = with a constant K. For example, if V o=2.5V, Io=15A, fs=300kHz, Co=1.68mF, R oesr=4.67mΩ, one can calculate that , m 167 I V R o o o Ω = = , 2 . 0 V 5 . 0 h o = = and . 14 . 7 1 . 2 I k o = = If the converter crossover frequency is set around 1/10 of the switching frequency, f c = 30kHz, the controller parameters then can be calculated as . nF 328 . 0 f 2 hkR g C c o m 2 ≈ π = where, gm is the error amplifier transconductance gain (260 µ Ω−1). If we use C 2 = 0.33 nF, , k 5 . 848 C C R R 2 o o 2 Ω ≈ = Application Information (Cont.) |
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