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ACE703 Datasheet(PDF) 8 Page - ACE Technology Co., LTD.

Part # ACE703
Description  White LED PFM Step-Up DC-DC Converter
PDF  16 Pages
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Manufacturer  ACE [ACE Technology Co., LTD.]
Direct Link  http://www.ace-ele.com
Logo ACE - ACE Technology Co., LTD.

ACE703 Datasheet(HTML) 8 Page - ACE Technology Co., LTD.

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ACE703
                        Technology
White LED PFM Step-Up DC-DC Converter
VER 1.2
8
Cf
R
D
Vout
Vout
r
load
=
Δ
=
Vout
R
ax
r
r
ESR
+
=
Im
'
1
2
1 +
=
R
R
V
Vout
IFB
2
)
1
(
R
V
Vout
IFB
×
Vout
Vout
I
C
L
Vout
L
+
Δ
2
2
(2) Capacitor Selection
Ignore ESR of capacitor, the ripple of output voltage is:
So large value capacitor is needed to reduce ripple. But too large capacitor value will slow down system
reaction and cost will improve. So 100uF capacitor is recommended. Larger capacitor value will be used
in large output current system. If output current is small (<10mA), small value is needed.
Consider ESR of capacitor, ripple will increase:
When current is large, ripple caused by ESR will be main factor. It may be greater than 100mV.The ESR
will affects efficiency and increase energy loss. So low-ESR capacitor (for example: tantalum capacitor) is
recommend or connect two or more filter capacitors in parallel.
(3) Diode Selection
Rectifier diode will affects efficiency greatly,Though a common diode (such as 1N4148) will work well for
light load, it will reduce about 5%~10% efficiency for heavy load, For optimum performance, a Schottky
diode (such as 1N5817.1N5819.1N5822) is recommended.
(4) Input Capacitor
If supply voltage is stable, the DC-DC circuit can output low ripple, low noise and stable voltage without
input capacitor. If voltage source is far away from DC-DC circuit, input capacitor value greater than 10uF
is recommended.
(5) Resistor R1.R2 for output voltage detect
In constant current application,R1 and R2 can be selected by following expression:
For example, when VIFB=400mV,Vout=3.3V.
If R2=4KΩ,then R1=
=29KΩ;if R2=40KΩ,then R1=290 KΩ.
(6) Selection of L.C and compensation capacitor C1
When the load current is large(eg: Iout=100mA),the output voltage ripple will increase:
As we can see, When output current is large, the maximum current of the inductor IL will increase, thus
the ripple of the output voltage will increase. To decrease the ripple, there are two ways:



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