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LM4898LD Datasheet(PDF) 14 Page - National Semiconductor (TI) |
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LM4898LD Datasheet(HTML) 14 Page - National Semiconductor (TI) |
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14 / 17 page ![]() Application Information (Continued) AUDIO POWER AMPLIFIER DESIGN Design a 1W/8 Ω Audio Amplifier Given: • Power Output 1W • Load Impedance 8 Ω • Input Level 1Vrms • Input Impedance 20k Ω • Bandwidth 100Hz–20kHz ± 0.25dB A designer must first determine the minimum supply rail to obtain the specified output power. The supply rail can easily be found by extrapolating from the Output Power vs. Supply Voltage graphs in the Typical Performance Characteristics section. A second way to determine the minimum supply rail is to calculate the required Vopeak using Equation 7 and add the dropout voltages. Using this method, the minimum sup- ply voltage is (Vopeak +(V DO TOP+(VDO BOT )),where VDO BOT and V DO TOP are extrapolated from the Dropout Voltage vs. Supply Voltage curve in the Typical Performance Char- acteristics section. (7) Using the Output Power vs. Supply Voltage graph for an 8 Ω load, the minimum supply rail just about 5V. Extra supply voltage creates headroom that allows the LM4898 to repro- duce peaks in excess of 1W without producing audible dis- tortion. At this time, the designer must make sure that the power supply choice along with the output impedance does not violate the conditions explained in the Power Dissipation section. Once the power dissipation equations have been addressed, the required differential gain can be determined from Equation 8. (8) R f /Ri =AVD From Equation 8, the minimum A VD is 2.83. Since the de- sired input impedance was 20k Ω, a ratio of 2.83:1 of R f to Ri results in an allocation of R i = 20k Ω for both input resistors and R f= 60k Ω for both feedback resistors. The final design step is to address the bandwidth requirement which must be stated as a single -3dB frequency point. Five times away from a -3dB point is 0.17dB down from passband response which is better than the required ±0.25dB specified. f H = 20kHz * 5 =100kHz The high frequency pole is determined by the product of the desired frequency pole, f H , and the differential gain, AVD .With a A VD = 2.83 and fH = 100kHz, the resulting GBWP = 150kHz which is much smaller than the LM4898 GBWP of 10MHz. This figure displays that if a designer has a need to design an amplifier with a higher differential gain, the LM4898 can still be used without running into bandwidth limitations. www.national.com 14 |
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