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MPZ2012S221A Datasheet(PDF) 31 Page - STMicroelectronics

Part # MPZ2012S221A
Description  38 V, 10 W synchronous iso-buck converter for isolated applications
PDF  56 Pages
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Manufacturer  STMICROELECTRONICS [STMicroelectronics]
Direct Link  http://www.st.com
Logo STMICROELECTRONICS - STMicroelectronics

MPZ2012S221A Datasheet(HTML) 31 Page - STMicroelectronics

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9
Application notes
9.1
Output voltage adjustment
Primary output voltage
The error amplifier reference voltage is 0.85 V typical. The output voltage is adjusted according to the equation
below:
VOUT_prim=0.85∙1+RFB1RFB2
(22)
where RFB1 and RFB2 are the resistors used in the output divider (see figure below).
Figure 37. Primary output voltage regulation
PGOOD
BOOT
SW
SW
VBIAS
FB
PGND
PGND
EP
GND
VOUT_prim
VOUT_iso
GND_iso
L6983I
CB
RFB1
RFB2
D
CSEC
COUT
A general recommendation is to keep the duty cycle below 50-60%. A higher duty cycle would limit off-time,
limiting the time in which the energy transfer to the secondary side takes place.
Other restrictions in the duty cycle selection arise due to the minimum on-time (see Section 9.2 Switching
frequency), generally summarized by the following equation:
D≥DMIN=TONMIN∙fSW
(23)
Secondary output voltage
In the iso-buck converter, the secondary output voltage is not included in the regulation loop. Nevertheless, a
good regulation of the secondary output voltage is achieved by relying on the primary output voltage regulation,
and the selection of a proper turn ratio of the transformer as well as considering the voltage drops due to the
secondary winding resistance and the Schottky diode. That can be summarized by the following equation:
VOUT_sec=N∙
[VOUT_prim+IOUT
pri ∙
(RDS(onLS+Rwind_pri)]∙ Lm
Lm+LLEAK
- Rwind_sec∙I
OUT_sec-VFD1
(24)
Where N is the turn ratio, Rwind_prim and Rwind_sec are the winding resistances of the primary and secondary
side respectively, VFD1 is the forward voltage of the Schottky diode, Lm is the magnetizing inductance of the
transformer and LLEAK the leakage inductance of the transformer.
If no current is drawn from the primary output, equation 24 can be simplified as follows:
VOUT_sec=N∙VOUTprim∙ Lm
Lm+LLEAK‐Rwind_sec∙IOUT_sec‐VFD1
(25)
L6983I
Application notes
DS14040 - Rev 1
page 31/56



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