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NX2142ACUTR Datasheet(PDF) 16 Page - Microsemi Corporation |
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NX2142ACUTR Datasheet(HTML) 16 Page - Microsemi Corporation |
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16 / 18 page ![]() NX2142/2142A 16 Rev. 1.1 10/28/07 Output Voltage Calculation Output voltage is set by reference voltage and external voltage divider. The reference voltage is fixed at 0.8V. The divider consists of two ratioed resistors so that the output voltage applied at the Fb pin is 0.8V when the output voltage is at the desired value. The following equation applies to figure 15, which shows the relationship between OUT V , REF V and voltage di- vider. Vout Vref Fb R2 R1 Figure 15 - Voltage divider 2 REF 1 OUT REF RV R= V -V × ...(21) where R 2 is part of the compensator, and the value of R1 value can be set by voltage divider. Input Capacitor Selection Input capacitors are usually a mix of high fre- quency ceramic capacitors and bulk capacitors. Ce- ramic capacitors bypass the high frequency noise, and bulk capacitors supply switching current to the MOSFETs. Usually 1uF ceramic capacitor is chosen to decouple the high frequency noise.The bulk input capacitors are decided by voltage rating and RMS cur- rent rating. The RMS current in the input capacitors can be calculated as: RMS OUT OUT INMIN I I D 1-D V D V = ×× = ...(22) VINMIN = 8V, VOUT=1.05V, IOUT=10A, the result of input RMS current is 3.4A. For higher efficiency, low ESR capacitors are recommended. One Sanyo OSCON CAP 25SVP56M = ×π ×× = ×π × Ω× = ESR OUT 1 F 2 ESRC 1 2 20.5m 1360uF 5.7kHz 2.Set R 2 equal to10kΩ. Using equation 18, the final selection of R 1 is 4.7kΩ. 3. Set crossover frequency at 1/10~ 1/5 of the swithing frequency, here FO=60kHz. 4.Calculate R 3 value by the following equation. OSC O OUT 3 in ESR m REF V2 F LV 1 R= V R gV 1 2 60kHz 2.2uH1 = 10 20.5m 2.5mA/V 2.5V 0.8V =5k ×π ×× × ×× ×π ×× ×× Ω × Ω Choose R 3 =5kΩ. 5. Calculate C 1 by setting compensator zero FZ at 75% of the LC double pole. 1 3z 1 C = 2 RF 1 = 2 5k 0.75 2.9kHz =14nF ×π ×× ×π × Ω ×× Choose C 1=15nF. 6. Calculate C 2 by setting compensator pole p F at half the swithing frequency. 2 3s 1 C = RF 1 = 5 k 600k Hz =54pF π ×× π × Ω× Choose C 2=52pF. |
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