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LT4180IGN-PBF Datasheet(PDF) 9 Page - Linear Technology |
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LT4180IGN-PBF Datasheet(HTML) 9 Page - Linear Technology |
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9 / 16 page ![]() LT4180 9 4180fp APPLICATIONS INFORMATION First determine the settling time (to 1% of final value) of the power supply. The settling time should be the worst-case value (over the whole operating envelope: VIN, ILOAD, etc.). F t Hz SETTLING 1 1 2 = • For example, if the power supply takes 1ms to settle (worst-case) to within 1% of final value: F e Hz 1 1 21 3 500 == •– Next, determine the propagation time of the wiring. In order to ignore transmission line effects, the dither period should be approximately twenty times longer than this. This will limit dither frequency to: F V ns ft L Hz F 2 20 1 017 = •. / • Where VF is the velocity factor (or velocity of propagation), and L is the length of the wiring (in feet). For example, assume the load is connected to a power supply with 1000ft of CAT5 cable. Nominal velocity of propagation is approximately 70%. F e kHz 2 07 20 1 017 9 1000 34 4 == . •. • . – The maximum dither frequency should not exceed F1 or F2 (whichever is less): fDITHER < min (F1, F2). Continuing this example, the dither frequency should be less than 500Hz (limited by the power supply). With the dither frequency known, the division ratio can be determined: D f f RATIO OSC DITHER == = 250 000 500 500 , The nearest division ratio is 512 (set DIV0 = L, DIV1 = DIV2 = H). Based on this division ratio, nominal dither frequency will be: f f D Hz DITHER OSC RATIO == = 250 000 512 488 , After the dither frequency is determined, the minimum load decoupling capacitor can be determined. This load capacitor must be sufficiently large to filter out the dither signal at the load. C Rf LOAD WIRE DITHER = 22 2 . •• Where CLOADistheminimumloaddecouplingcapacitance, RWIRE is the minimum wiring resistance of one conduc- tor of the wiring pair, and fDITHER is the minimum dither frequency. Continuing the example, our CAT5 cable has a maximum 9.38Ω/100m conductor resistance. Maximum wiring resistance is: RWIRE = 2 • 1000ft • 0.305m/ft • 0.0938Ω/m RWIRE = 57.2Ω |
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