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AN2928 Datasheet(PDF) 14 Page - STMicroelectronics

Part # AN2928
Description  Modified buck converter for LED applications
PDF  21 Pages
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Manufacturer  STMICROELECTRONICS [STMicroelectronics]
Direct Link  http://www.st.com
Logo STMICROELECTRONICS - STMicroelectronics

AN2928 Datasheet(HTML) 14 Page - STMicroelectronics

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Design equations for the modified buck converter
AN2928
14/21
Finally, if the heat sink and its thermal resistance is known, it is possible to calculate
maximum static drain-source on resistance from Equation 26, Equation 27 and Equation 28
for easy power MOSFET selection.
Equation 29
2.5
Power diode selection
The power diode (D1 from Figure 1) is chosen based on its maximum stress voltage, its
maximum peak current and total power losses. The power losses are lower for a larger duty
cycle and vice-versa, because the diode is opened (connected) during off-time.
Maximum voltage stress across the diode is equal to the input voltage VIN, and therefore the
power diode must be selected with some voltage margin. For example, if the input voltage is
maximally 400 V, then maximum repetitive peak reverse voltage (VRRM) should be 450 V or
higher.
Maximum peak diode current is selected in order to calculate the inductor size in
Equation 20. Also in this case, the power diode must be selected with some current margin.
Power losses are generally calculated with the following equation:
Equation 30
PLOSS_D = power diode losses (W)
iD = power diode current (A)
uD = power diode voltage (V)
And assuming a constant voltage drop over the diode it is possible to approximately
calculate the power losses on the diode (switching losses are not included) with the
following equation:
Equation 31
IAVR_D = power diode average current (A)
VF = power diode forward voltage for calculated average diode current (V)
R
DS ON
()
T
JMAX
T
A
–
R
th JC
R
th C H
R
th HA
++
() l
RM S
2
⋅
-------------------------------------------------------------------------------------
V
IN
l
MAX
t
OFF SW
f
⋅⋅
⋅
2l
RMS
2
⋅
--------------------------------------------------------------------
–
<
P
LOSS D
1
T
---
i
D t
() u
D
⋅
t
() t
d
0
T
∫
=
P
LOSS D
I
AVR D
V
F
⋅
=



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