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DAP018x Marking, DAP018DDR2G Datasheet(PDF) 25 Page - ON Semiconductor

Part # DAP018DDR2G
Description  PWM Current-Mode Controller for High-Power Universal Off-Line Supplies
PDF  28 Pages
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Manufacturer  ONSEMI [ON Semiconductor]
Direct Link  http://www.onsemi.com
Logo ONSEMI - ON Semiconductor

DAP018DDR2G Datasheet(HTML) 25 Page - ON Semiconductor

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DAP018A/B/C/D/F
http://onsemi.com
25
65kHz
68.9kHz
61.1kHz
adjustable
Figure 50. Modulation Effects on the Clock Signal by the Jittering Sawtooth
Jitter ramp
Internal
sawtooth
Over Power Protection
There are several known ways to implement Over Power
Protection (OPP), all suffering from particular problems.
These problems range from the added consumption burden
on the converter or the skip−cycle disturbance brought by
the current−sense offset. A way to reduce the power
capability at high line is described by Figure 52. On this
drawing, a voltage is derived from the auxiliary winding and
produces a negative level during the on−time of the main
power transistor. The negative voltage amplitude directly
relates to the input level via the transformer turn ratio linking
the primary winding to the auxiliary winding. Figure 51
depicts the typical signal obtained on the auxiliary winding:
1 v(24)
464u
472u
480u
488u
496u
time in seconds
−40.0
−20.0
0
20.0
40.0
1
1
−40.0
−20.0
0
20.0
40.0
1
Figure 51. The Signal Obtained on the Auxiliary Winding Swings Negative During the On−time
off−time
on−time
N1(Vout + Vf)
−N2Vbulk
During the off−time, the voltage plateaus to a positive
level depending on the turn ratio between the output winding
(Ns) and the power winding. This ratio is noted N1. During
the on−time, the transformer terminal swings to a negative
voltage whose amplitude now depends on the turn ratio N2,
equal to the primary (Np) to the auxiliary winding ratio
(Naux). If we place a resistive divider between the auxiliary
winding and the OPP pin, as suggested by Figure 52, we
have a means to influence the internal setpoint as the bulk
voltage increases. The equations to design the network are
fairly simple:
Suppose we need to reduce the peak current from 2.5 A at
low line, to 2 A at high line. This corresponds to 20%
reduction or a setpoint voltage of 640 mV. To reach this
level, then the negative voltage developed on the OPP pin
must reach:
VOPP + 800 * 640 + −160 mV
(eq. 4)



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