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AN1882 Datasheet(PDF) 18 Page - STMicroelectronics |
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AN1882 Datasheet(HTML) 18 Page - STMicroelectronics |
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18 / 30 page ![]() Application information AN1882 18/30 Doc ID 10209 Rev 4 5.1.4 Compensation network (R1C3) As it is shown in the Section 3.2 the system stability can be studied with the loop transfer function given by the Equation 3Equation 3. If the output capacitor is a ceramic type the zero due to the ESR generally will be out of the system bandwidth, so the stability of the system will be ensured by the cancellation between the pole due to the output capacitor and the equivalent load and the R1C3 zero. In the Equation 15Equation 15, a simplified gain loop expression, valid around the transition frequency fT is given by: Equation 15 Supposing C2 = 22 µF, the transition frequency at 0 dB equal to 30 kHz (fT is equal to the system bandwidth), and the output voltage equal to 1.8 V the R1 value can be calculated as: Equation 16 The nearest standard E12 series value is R1 = 47 kΩ. The higher is the bandwidth, the faster will be the transient response but the bandwidth (and so the R1 value) must be lower than fSW/10 to avoid the effect due to the sampling effect poles as mentioned in the Section 3.2. The zero due to the compensation network must be at the least 5 times before the frequency transition, so the C3 value will be: Equation 17 The nearest standard value is C3 = 470 pF. If the output capacitors are tantalum type the ESR zero is in the system bandwidth and it can be used to stabilize the system so the zero due to the compensation network will be useless (the C3 is necessary to the integrator function). 5.2 Losses and efficiency There are losses affecting the efficiency of the application. Some of these losses are related to the device and others are related to the external components. The most important losses are listed below. 5.2.1 Conduction losses These losses are basically due to the not negligible resistances of the internal switches and the external inductor. Usually the current ripple across the inductor is negligible and so to estimate the conduction losses of the inductor, the average output current can be considered. The conduction losses of the switches depend also on the duty cycle of the application. The RMS current flowing through the high side MOSFET is (IO) 2 · D while the RMS current flowing through the low side MOSFET is (IO) 2 · (1-D). So, the total conduction losses are: G LOOP s () g mR1α sC 2 ------------------- = R 1 2 πf TC2 g mα ------------------- = C 3 5 2 πf TR1 ------------------- 500pF = = |
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