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HMC832LP6GETR Datasheet(PDF) 28 Page - Analog Devices |
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HMC832LP6GETR Datasheet(HTML) 28 Page - Analog Devices |
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28 / 49 page ![]() Data Sheet HMC832 Using Exact Frequency Mode If the constraint in Equation 16 is satisfied, the HMC832 is able to generate signals with zero frequency error at the desired VCO frequency. Exact frequency mode can be reconfigured for each target frequency, or be setup for a fixed fGCD that applies to all channels. Configuring Exact Frequency Mode for a Particular Frequency 1. Calculate and program the integer register setting Register 0x03 = NINT = floor(fVCO/fPD) where the floor function is the rounding down to the nearest integer. 2. Then calculate the integer boundary frequency fN = NINT × fPD. 3. Calculate and program the exact frequency register value Register 0x0C = fPD/fGCD where fGCD = GCD(fVCO,fPD). 4. Calculate and program the fractional register setting Register 0x04 − = PD N VCOk FRAC f f f ceil N ) ( 2 24 where ceil is the ceiling function meaning round up to the nearest integer. Example: to configure the HMC832 for exact frequency mode at fVCO = 2800.2 MHz, where the PD rate (fPD) = 61.44 MHz, proceed as follows: 1. Check Equation 16 to confirm that the exact frequency mode for this fVCO is possible. ≥ = 14 2 ) , ( PD GCD PD VCO GCD f f and f f GCD f fGCD = GCD(2800.2 × 106, 61.44 × 106) = 120 × 103 > 14 6 2 10 44 . 61 × = 3750 Because Equation 16 is satisfied, the HMC832 can be configured for exact frequency mode at fVCO = 2800.2 MHz by continuing with the remaining steps. 2. Calculate NINT NINT = Register 0x03 = D 2 x 0 d 45 10 44 . 61 10 2 . 2800 6 6 1 = = × × = floor f f floor PD VCO 3. Calculate the value for Register 0x0C Register 0x0C = 00 xC 0 d 3072 20000 10 44 . 61 ) 10 44 . 61 , 10 100 ( 10 44 . 61 ) ), (( 6 6 3 6 1 = = × = × × × = − + GCD f f f GCD f PD VCOk VCOk PD 4. To program Register 0x04, the closest integer-N boundary frequency (fN) that is less than the desired VCO frequency (fVCO) must be calculated: fN = fPD × NINT. Using the current example fN = fPD × NINT = 45 × 61.44 × 106 = 2764.8 MHz, then Register 0x04 = 938000 x 0 d 9666560 10 44 . 61 ) 10 8 . 2764 10 2 . 2800 ( 2 ) ( 2 6 6 6 24 24 = = × × − × = − ceil f f f ceil PD N VCO Exact Frequency Channel Mode When multiple, equally spaced, exact frequency channels are needed that fall within the same interval (that is, fN ≤ fVCOk < fN + 1) where fVCOk is shown in Figure 46 and 1 ≤ k ≤ 214, it is possible to maintain the same integer-N (Register 0x03) and exact frequency register (Register 0x0C) settings and only update the fractional register (Register 0x04) setting. The exact frequency channel mode is possible when Equation 16 is satisfied for at least two equally spaced adjacent frequency channels, that is, the channel step size. To configure the HMC832 for exact frequency channel mode, initially and only at the beginning, the integer (Register 0x03) and exact frequency (Register 0x0C) registers need to be programmed for the smallest fVCO frequency (fVCO1 in Figure 46), as follows: 1. Calculate and program the integer register setting Regis- ter 0x03 = NINT = floor(fVCO1/fPD), where fVCO1 is shown in Figure 46 and corresponds to the minimum channel VCO frequency. Then, the lower integer boundary frequency is given by fN = NINT × fPD. 2. Calculate and program the exact frequency register value Register 0x0C = fPD/fGCD, where fGCD = GCD((fVCOk+1 − fVCOk), fPD) = greatest common divisor of the desired equidistant channel spacing and the PD frequency ((fVCOk + 1 − fVCOk) and fPD). Rev. A | Page 27 of 48 |
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